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11x^2-77x-36=0
a = 11; b = -77; c = -36;
Δ = b2-4ac
Δ = -772-4·11·(-36)
Δ = 7513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-77)-\sqrt{7513}}{2*11}=\frac{77-\sqrt{7513}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-77)+\sqrt{7513}}{2*11}=\frac{77+\sqrt{7513}}{22} $
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